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x > y > 0
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16 Apr 2018, 15:32
16 Apr 2018, 15:32
Expert Reply
00:00
Question Stats:
73% (00:51) correct
26% (01:01) wrong based on 52 sessions
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\(x > y > 0\)
Quantity A |
Quantity B |
\(x - y\) |
\(\frac{x}{3} + \frac{y}{3}\) |
A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Re: x > y > 0
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18 Apr 2018, 02:05
18 Apr 2018, 02:05
2
simplify the given quantities
\(x -y\) \(?\) \(x+y/3\)
\(3x - 3y ? x + y\)
subtracting x from both sides
\(2x - 3y ? y\)
subtracting y from both sides
\(2x -4y ? 0\)
adding 4y to both sides
\(2x ? 4y\)
Dividing both sides by \(2\)
\(x ? 2y\)
we know that \(x > y\) but we do not know by how much so
it could be the case that \(x =4\) and \(y =2\) so both quantities are equal or
\(x = 100\) and \(y = 10\) and as such \(2y =20\)
A>B
Therefore option D
\(x -y\) \(?\) \(x+y/3\)
\(3x - 3y ? x + y\)
subtracting x from both sides
\(2x - 3y ? y\)
subtracting y from both sides
\(2x -4y ? 0\)
adding 4y to both sides
\(2x ? 4y\)
Dividing both sides by \(2\)
\(x ? 2y\)
we know that \(x > y\) but we do not know by how much so
it could be the case that \(x =4\) and \(y =2\) so both quantities are equal or
\(x = 100\) and \(y = 10\) and as such \(2y =20\)
A>B
Therefore option D
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Re: x > y > 0
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23 May 2021, 22:39
23 May 2021, 22:39
amorphous wrote:
simplify the given quantities
\(x -y\) \(?\) \(x+y/3\)
\(3x - 3y ? x + y\)
subtracting x from both sides
\(2x - 3y ? y\)
subtracting y from both sides
\(2x -4y ? 0\)
adding 4y to both sides
\(2x ? 4y\)
Dividing both sides by \(2\)
\(x ? 2y\)
we know that \(x > y\) but we do not know by how much so
it could be the case that \(x =4\) and \(y =2\) so both quantities are equal or
\(x = 100\) and \(y = 10\) and as such \(2y =20\)
A>B
Therefore option D
\(x -y\) \(?\) \(x+y/3\)
\(3x - 3y ? x + y\)
subtracting x from both sides
\(2x - 3y ? y\)
subtracting y from both sides
\(2x -4y ? 0\)
adding 4y to both sides
\(2x ? 4y\)
Dividing both sides by \(2\)
\(x ? 2y\)
we know that \(x > y\) but we do not know by how much so
it could be the case that \(x =4\) and \(y =2\) so both quantities are equal or
\(x = 100\) and \(y = 10\) and as such \(2y =20\)
A>B
Therefore option D
This is bit easy and less time consuming.
