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O is the center of both circles
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25 May 2021, 19:46
25 May 2021, 19:46
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Question Stats:
79% (01:06) correct
20% (00:59) wrong based on 43 sessions
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Attachment:
GRE O is the center of both circles.jpg [ 12.29 KiB | Viewed 4387 times ]
O is the center of both circles
Quantity A |
Quantity B |
The area of the circular region with radius OP |
The area of the shaded sector ROQ |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
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O is the center of both circles
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26 May 2021, 08:59
26 May 2021, 08:59
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Carcass wrote:
Attachment:
GRE O is the center of both circles.jpg
O is the center of both circles
Quantity A |
Quantity B |
The area of the circular region with radius OP |
The area of the shaded sector ROQ |
Both of the diagrams above satisfy the given information (since we aren't told the radii of the circles or the central angle of the sector).
In the diagram on the left, quantity A is greater than quantity B
In the diagram on the right, quantity B is greater than quantity A
So the correct answer is D
(I've edited the official answer to reflect this)
Cheers,
Brent
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Status:Founder & Quant Trainer
Affiliations: Prepster Education
Posts: 1546
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WE:Education (Education)
Re: O is the center of both circles
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26 May 2021, 09:15
26 May 2021, 09:15
1
Carcass wrote:
Attachment:
GRE O is the center of both circles.jpg
O is the center of both circles
Quantity A |
Quantity B |
The area of the circular region with radius OP |
The area of the shaded sector ROQ |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Let OP = 2 and PQ = 1
So, OQ = 3
Col. A: \(π2^2\)
Col. B: \((\frac{θ}{360})π3^2\)
Col. A: \(4π\)
Col. B: \((\frac{θ}{360})9π\)
Col. A: \(4\)
Col. B: \(\frac{9θ}{360}\)
Col. A: \((360)(4)\)
Col. B: \(9θ\)
Col. A: \(160\)
Col. B: \(θ\)
We have no idea what \(θ\) is!
Hence, option D
