GreenlightTestPrep wrote:
This is a tough one to use the INPUT-OUTPUT approach, but here is goes:
Let c = $2 (it cost $2 to make each umbrella)
Let x = 10 (we make 10 umbrellas)
Let r = $5 (the retail price is $5 per umbrella)
Let b = $0 (the below-cost sale price is $0 per umbrella)
So, the manufacturer made 10 umbrellas at the cost of $2 per umbrella. So the total cost = $20
We need a 100% profit. So, we must earn $40 in revenue. In other words, we must sell 8 umbrellas at $5 each.
This means we can "sell" 2 umbrellas at the below-cost sale price of $0 each.
At this point, we must plug c = 2, x = 10, r = 5 and b = 0 into each expression and see which one yields an OUTPUT of 2
A. \(\frac{b(2c-r)}{(x-r)}\) = 0 ELIMINATE A
B. \(\frac{2x(c-r)}{(b-r)}\) = 12 ELIMINATE B
C. \(\frac{x(2c-r)}{(b-r)}\) = 2 KEEP C
D. \(\frac{2b(c-r)}{(x-r)}\) = 0 ELIMINATE D
E. \(\frac{2(xc-r)}{(x-r)}\) = 6 ELIMINATE E
Answer : C
Thank you sir for the explanation
Regards