Both inequalities are likely to give you a range of values as solutions x and y. We need to find whether solutions x and y overlap. If the solutions overlap, we may not be able to make comparison. Otherwise, we can compare.

So, we will have to solve the given inequalities.

1. 4x - 2x ≤ 10 + 14 - 8
2x ≤ 16
x ≤ 8

2. Coverting the expression under the root,
$16 - 8y + y^2 = (y - 4)^2$

Solving the given inequality,
$(16 - 8y + y^2)^\frac{1}{2} ≤ 9$

$((y - 4)^2)^\frac{1}{2} ≤ 9$

$| y - 4 | ≤ 9$
Solving this absolute value expression by distances on the number line,
-5 ≤ y ≤ 13

We see that the solutions x and y overlap.
Hence, D is the correct answer.