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If 3(x + 1) + 3(x − 1) = 10/27 , what is the value of x?
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Updated on: 08 Mar 2017, 11:19
Updated on: 08 Mar 2017, 11:19
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If 3(x + 1) + 3(x − 1) = \(\frac{10}{27}\) , what is the value of x?
1. 3
2. 2
3. \(\frac{1}{2}\)
4. \(\frac{-1}{2}\)
5. −2
1. 3
2. 2
3. \(\frac{1}{2}\)
4. \(\frac{-1}{2}\)
5. −2
Originally posted by shadowcatradz on 08 Mar 2017, 04:37.
Last edited by Carcass on 08 Mar 2017, 11:19, edited 2 times in total.
Last edited by Carcass on 08 Mar 2017, 11:19, edited 2 times in total.
Edited by Carcass
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Re: If 3(x + 1) + 3(x − 1) = 10/27 , what is the value of x?
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24 Mar 2017, 06:17
24 Mar 2017, 06:17
1
shadowcatradz wrote:
If 3(x + 1) + 3(x − 1) = \(\frac{10}{27}\) , what is the value of x?
1. 3
2. 2
3. \(\frac{1}{2}\)
4. \(\frac{-1}{2}\)
5. −2
1. 3
2. 2
3. \(\frac{1}{2}\)
4. \(\frac{-1}{2}\)
5. −2
Expand to get: 3x + 3 + 3x - 3 = 10/27
Simplify: 6x = 10/27
Divide both sides by 6 to get: x = (10/27)/6 = (10/27)(1/6) = 5/81
Are you sure you transcribed the question correctly?
Cheers,
Brent
gmatclubot
Re: If 3(x + 1) + 3(x − 1) = 10/27 , what is the value of x? [#permalink]
24 Mar 2017, 06:17
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