Let the side of equilateral triangle be a
So, 3a = p
i.e. a = $\frac{p}{3}$

Also, side of equilateral triangle = side of square = diameter of semi-circle = $\frac{p}{3}$

Half-circumference of circle = $πr = \frac{πp}{6}$
Perimeter of other fours sides of the figure = $4(\frac{p}{3})$

Total Perimeter = $\frac{4p}{3} + \frac{πp}{6}$

Hence, option E