GeminiHeat wrote:
Barry walks from one end to the other of a 30-meter long moving walkway at a constant rate in 30 seconds, assisted by the walkway. When he reaches the end, he reverses direction and continues walking with the same speed, but this time it takes him 120 seconds because he is traveling against the direction of the moving walkway. If the walkway were to stop moving, how many seconds would it take Barry to walk from one end of the walkway to the other?
A) 48
B) 60
C) 72
D) 75
E) 80
Let the speed of Barry be \(B\) and speed of the walkway be \(W\)
Case I: Moving along the walkway\(S = \frac{D}{T}\)
\(B+W = \frac{30}{30}\)
\(B+W = 1\)
Case II: Moving against the walkway\(S = \frac{D}{T}\)
\(B-W = \frac{30}{120}\)
\(B-W = \frac{1}{4}\)
Solve both the equations to get \(B = \frac{5}{4}\)
Therefore, time required by Barry = \(30(\frac{4}{5}) = 48\) seconds
Hence, option A