In Normal Distribution or Bell-curve;
Distribution \(= x̅ ± xσ\)

Where,
\(x̅\) = Mean
\(σ\) = Standard Deviation (SD)
\(x\) = Deviation from the Mean (0 to 3)

1 SD above Mean = \(74 + 7 = 81\)
2 SD above Mean = \(74 + (2)7 = 88\)
3 SD above Mean = \(74 + (3)7 = 95\)

1 SD below Mean = \(74 - 7 = 67\)
2 SD below Mean = \(74 - (2)7 = 60\)
3 SD below Mean = \(74 - (3)7 = 53\)

A. More students scored above 83 than scored below 63
Refer to the graph below; 83 lies between 2 SD and 3 SD above Mean (NEAR to 1 SD) whereas, 63 lies somewhere in the middle of 2SD and 3 SD below Mean. Notice the un-shaded region in the right is greater than the un-shaded region in the left

B. At least 65% of students scored between 67 and 81
Refer to the figure below, approximately \(\frac{2}{3}^{rd}\) of the data lies between 1 SD above and 1 SD below Mean

C. More than half the students scored above 75
In Normal Distribution 50% of data lies above the Mean and 50% data lies below it

Hence, Option A and B