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solve (x^2+7x+2)/(x-2)>2, x range?
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04 Jun 2021, 14:24
04 Jun 2021, 14:24
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\(\frac{x^2+7x+2}{x-2}>2\) , range of x is?
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GMAT 1: 700 Q51 V31
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solve (x^2+7x+2)/(x-2)>2, x range?
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06 Jun 2021, 09:09
06 Jun 2021, 09:09
2
Let's Learn to Solve Inequalities!
\(\frac{x^2+7x+2}{x-2}>2\)
Take 2 to left hand side, we get
\(\frac{x^2+7x+2}{x-2} - 2 > 0\)
=> \(\frac{x^2+7x+2 - 2*(x-2) }{x-2}>0\)
=> \(\frac{x^2+7x+2 - 2x + 4 }{x-2}>0\)
=> \(\frac{x^2+5x+6}{x-2}>0\)
=> \(\frac{x^2+2x + 3x +6}{x-2}>0\)
=> \(\frac{x(x+2) + 3(x +2)}{x-2}>0\)
=> \(\frac{(x+2)* (x+3)}{x-2}>0\)
Multiply numerator and denominator on left hand side by x-2 we get
=> \(\frac{(x+2)* (x+3) * (x-2)}{(x-2)^2}>0\)
Denominator is \((x-2)^2\) which will anyways be > 0 so we can ignore this to solve the problem
So, question reduces to (x+2)* (x+3) * (x-2) > 0
Follow this post to learn about Sine curve method of solving the problem to follow the method
Points on the sign curve will be -3, -2, 2 [ we get this by putting x+3 = 0, x+2=0, x-2 = 0]
See below image
Image.jpg [ 40.3 KiB | Viewed 2511 times ]
Since question is asking for > 0 so answer will be the values indicated in the "+" region in the above image
So, answer is -3<x<-2 and x>2.
Check answer by substituting and tell me if it works!
Hope it helps!
Watch the following video to learn How to Solve Inequality Problems
\(\frac{x^2+7x+2}{x-2}>2\)
Take 2 to left hand side, we get
\(\frac{x^2+7x+2}{x-2} - 2 > 0\)
=> \(\frac{x^2+7x+2 - 2*(x-2) }{x-2}>0\)
=> \(\frac{x^2+7x+2 - 2x + 4 }{x-2}>0\)
=> \(\frac{x^2+5x+6}{x-2}>0\)
=> \(\frac{x^2+2x + 3x +6}{x-2}>0\)
=> \(\frac{x(x+2) + 3(x +2)}{x-2}>0\)
=> \(\frac{(x+2)* (x+3)}{x-2}>0\)
Multiply numerator and denominator on left hand side by x-2 we get
=> \(\frac{(x+2)* (x+3) * (x-2)}{(x-2)^2}>0\)
Denominator is \((x-2)^2\) which will anyways be > 0 so we can ignore this to solve the problem
So, question reduces to (x+2)* (x+3) * (x-2) > 0
Follow this post to learn about Sine curve method of solving the problem to follow the method
Points on the sign curve will be -3, -2, 2 [ we get this by putting x+3 = 0, x+2=0, x-2 = 0]
See below image
Attachment:
Image.jpg [ 40.3 KiB | Viewed 2511 times ]
Since question is asking for > 0 so answer will be the values indicated in the "+" region in the above image
So, answer is -3<x<-2 and x>2.
Check answer by substituting and tell me if it works!
Hope it helps!
Watch the following video to learn How to Solve Inequality Problems
General Discussion
Re: solve (x^2+7x+2)/(x-2)>2, x range?
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04 Jun 2021, 19:22
04 Jun 2021, 19:22
1
Sir, it would be great if you provide the OA.
