Detailed explanation

Now we know slope of line\(m = \frac{(y2 - y1 )}{(x2 -x1)}\)

Therefore the slope of line\(l= \frac{(y2 - y1 )}{(x2 -x1)}\) [ where y2 = \(-\sqrt{3}\), y1 =\(\sqrt{3}\)and x2 = \(\sqrt{2}\) and x1 =\(-\sqrt{2}\) ]

\(=(-\sqrt{3}-\sqrt{3})/(\sqrt{2}+\sqrt{2})\)

\(= -\sqrt{3}/\sqrt{2}\)

Now slope of line \(M = \sqrt{2}/\sqrt{3}\) (Since the slope M is perpendicular to line l and we know the slope is negative reciprocal)

Hence option B is greater since it is positive value