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Joined: 20 Feb 2017
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In a certain lottery drawing, five balls are selected from a tumbler
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10 Jun 2021, 22:05
10 Jun 2021, 22:05
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In a certain lottery drawing, five balls are selected from a tumbler in which each ball is printed with a different two-digit positive integer. If the average (arithmetic mean) of the five numbers drawn is 56 and the median is 60, what is the greatest value that the lowest number selected could be?
A) 43
B) 48
C) 51
D) 53
E) 56
A) 43
B) 48
C) 51
D) 53
E) 56
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Joined: 02 Jan 2020
Status:GRE Quant Tutor
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Concentration: General Management
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GMAT 1: 700 Q51 V31
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Re: In a certain lottery drawing, five balls are selected from a tumbler
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13 Jun 2021, 02:50
13 Jun 2021, 02:50
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We have five different 2 digit numbers whose average is 56 and median is 60
Since the Median is 60 => the middle number is 60
Average of the number is 56 => Sum = 5*56 = 280
Now we have to find the greatest possible value of lowest number=> numbers greater than 60 should be smallest
=> x , y ,60,61,62 should be other numbers (where x and y are the two numbers smaller than 60, x being the smallest)
=> x + y + 60 + 61 + 62 = 280
=> x + y = 97
Now, for x to be maximum, y should be minimum
Minimum value of y will be x + 1 (as y cannot be less than x and x has to be greatest)
x + x + 1 = 97
=> x = 48, y = 49
So, answer will be B
Hope it helps!
Since the Median is 60 => the middle number is 60
Average of the number is 56 => Sum = 5*56 = 280
Now we have to find the greatest possible value of lowest number=> numbers greater than 60 should be smallest
=> x , y ,60,61,62 should be other numbers (where x and y are the two numbers smaller than 60, x being the smallest)
=> x + y + 60 + 61 + 62 = 280
=> x + y = 97
Now, for x to be maximum, y should be minimum
Minimum value of y will be x + 1 (as y cannot be less than x and x has to be greatest)
x + x + 1 = 97
=> x = 48, y = 49
So, answer will be B
Hope it helps!
gmatclubot
Re: In a certain lottery drawing, five balls are selected from a tumbler [#permalink]
13 Jun 2021, 02:50
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