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The height, h, of a thrown ball as a function of t, the amount of time
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16 Jun 2021, 02:05
16 Jun 2021, 02:05
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73% (01:29) correct
26% (01:10) wrong based on 23 sessions
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The height, h, of a thrown ball as a function of t, the amount of time it has been in the air, is given by \(h(t) = –10t^2 + 40t\). What is the maximum height attained by the ball?
2
20
40
80
160
2
20
40
80
160
The height, h, of a thrown ball as a function of t, the amount of time
[#permalink]
16 Jun 2021, 02:57
16 Jun 2021, 02:57
1
given
\(h(t)=–10t^2+40th(t)=–10t^2+40t\)
for getting maximum height differentiate the equation on both sides
-20t+40 = 0
t = 2
maximum height will be attainted at t=2sec
so h=80-40=40
option C is correct
\(h(t)=–10t^2+40th(t)=–10t^2+40t\)
for getting maximum height differentiate the equation on both sides
-20t+40 = 0
t = 2
maximum height will be attainted at t=2sec
so h=80-40=40
option C is correct
Re: The height, h, of a thrown ball as a function of t, the amount of time
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18 Jun 2021, 05:02
18 Jun 2021, 05:02
I still did not get the explanation. Can someone please explain the solution in detail?
thanks
thanks
