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G is the sequence of numbers g1, g2, g3…gn such that each te
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23 Apr 2020, 09:35
23 Apr 2020, 09:35
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Question Stats:
63% (02:23) correct
36% (03:12) wrong based on 36 sessions
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\(G\) is the sequence of numbers \(g_1, g_2, g_3…g_n\) such that each term following the first is one more than two times the preceding term. If \(g_2 + g_4 = 30 \frac{1}{2}\), what is the first term in the sequence?
A. \(\frac{3}{4}\)
B. \(1\)
C. \(\frac{3}{2}\)
D. \(\frac{9}{4}\)
E. \(\frac{7}{2}\)
A. \(\frac{3}{4}\)
B. \(1\)
C. \(\frac{3}{2}\)
D. \(\frac{9}{4}\)
E. \(\frac{7}{2}\)
Re: G is the sequence of numbers g1, g2, g3…gn such that each te
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31 May 2020, 18:46
31 May 2020, 18:46
1
Hmmm not sure what's going on here.
Here's what I got:
g1 = ?
g2 = 2g1 + 1
g3 = 4g1 + 3
g4 = 8g1 + 7
g1 + g4 = 9g1 + 7
9g1+ 7 = 30.5 = 61/2
9g1 = 47/2
g1 = 47/18
What'd I do wrong?
Here's what I got:
g1 = ?
g2 = 2g1 + 1
g3 = 4g1 + 3
g4 = 8g1 + 7
g1 + g4 = 9g1 + 7
9g1+ 7 = 30.5 = 61/2
9g1 = 47/2
g1 = 47/18
What'd I do wrong?
Re: G is the sequence of numbers g1, g2, g3…gn such that each te
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01 Jun 2020, 11:58
01 Jun 2020, 11:58
i also got 47/18. working back from the supposed answer, the addition of the two terms doesn't also add up to 30.5. My conclusion therefore, is that either a vital information is missing, or the question is wrong.
