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0 > x > y > z > -1
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01 Oct 2017, 22:31
01 Oct 2017, 22:31
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Question Stats:
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62% (01:24) wrong based on 35 sessions
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\(0 > x > y > z > -1\)
A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Kudos for correct solution.
Quantity A |
Quantity B |
x/y |
y/z |
A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Kudos for correct solution.
Re: 0 > x > y > z > -1
[#permalink]
01 Oct 2017, 23:33
01 Oct 2017, 23:33
2
Bunuel wrote:
\(0 > x > y > z > -1\)
A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Kudos for correct solution.
Quantity A |
Quantity B |
x/y |
y/z |
A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Kudos for correct solution.
Now lets consider two values
1st case let x=-0.1 , y =-0.2 . z =-0.3 (since we have to maintain the statement 0>x>y>z>-1)
Now QTY A = \(\frac{x}{y} = \frac{-0.1}{-0.2} = 0.5\)
QTY B = \(\frac{y}{z}= \frac{-0.2}{-0.3}= 0.6\)
Here QTY b >QTY a
Again if we consider
x=-0.2 , y =-0.4 . z =-0.9
Now QTY A = \(\frac{x}{y}= -\frac{0.2}{-0.4} = 0.5\)
QTY B = \(\frac{y}{z} =\frac{-0.4}{-0.9} = 0.4\)
So QTY a >QTY b.
Hence the option is D
Re: 0 > x > y > z > -1
[#permalink]
08 Jul 2021, 06:27
08 Jul 2021, 06:27
Hello from the GRE Prep Club BumpBot!
Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
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Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
