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Willard can paint a room in 6 hours working alone. Jada can do the sam
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09 Jul 2021, 07:39
09 Jul 2021, 07:39
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Question Stats:
83% (00:53) correct
16% (01:01) wrong based on 67 sessions
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Willard can paint a room in 6 hours working alone. Jada can do the same job in 4 hours working alone.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
The number of hours it should take Willard and Jada to paint the room working together |
\(2 \frac{1}{2}\) hours |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Willard can paint a room in 6 hours working alone. Jada can do the sam
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09 Jul 2021, 08:03
09 Jul 2021, 08:03
3
Formula :
When a person can do a job in \(x\) hours and another do the same job in \(y\) hours,
then the time needed when both work together to complete the job = \(\frac{xy}{x+y}\)
Qt A
Time = \(\frac{6*4}{6+4}\) = \(2\frac{2}{5}\)
Qt B > Qt A
Answer B
When a person can do a job in \(x\) hours and another do the same job in \(y\) hours,
then the time needed when both work together to complete the job = \(\frac{xy}{x+y}\)
Qt A
Time = \(\frac{6*4}{6+4}\) = \(2\frac{2}{5}\)
Qt B > Qt A
Answer B
Re: Willard can paint a room in 6 hours working alone. Jada can do the sam
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19 Nov 2022, 06:30
19 Nov 2022, 06:30
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Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
