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Find the greatest number that will divide 43, 91 and 183 so as to leav
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09 Jul 2021, 08:43
09 Jul 2021, 08:43
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Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.
A. 4
B. 7
C. 9
D. 13
E. 24
A. 4
B. 7
C. 9
D. 13
E. 24
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Re: Find the greatest number that will divide 43, 91 and 183 so as to leav
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09 Jul 2021, 08:53
09 Jul 2021, 08:53
1
Carcass wrote:
Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.
A. 4
B. 7
C. 9
D. 13
E. 24
A. 4
B. 7
C. 9
D. 13
E. 24
This question lends itself to testing the answer choices
Since we're looking for the greatest number, we'll start at E and work our way to A
E) 24
43 divided by 24 equals 1 with remainder 19
91 divided by 24 equals 3 with remainder 19
183 divided by 24 equals 7 with remainder 15
We need the SAME remainder each time - ELIMINATE E
D) 13
43 divided by 13 equals 3 with remainder 4
91 divided by 13 equals 7 with remainder 0
We need the SAME remainder each time - ELIMINATE D
C) 9
43 divided by 9 equals 4 with remainder 7
91 divided by 9 equals 10 with remainder 1
We need the SAME remainder each time - ELIMINATE C
B) 7
43 divided by 7 equals 6 with remainder 1
91 divided by 7 equals 13 with remainder 0
We need the SAME remainder each time - ELIMINATE B
By the process of elimination, the correct answer is A
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Re: Find the greatest number that will divide 43, 91 and 183 so as to leav
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02 Oct 2022, 09:49
02 Oct 2022, 09:49
We need to find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.
A. 4
43, 91, 183 each when divided by 4 gives 3 remainder => POSSIBLE
B. 7
43 when divided by 7 gives 1 remainder
91 when divided by 7 gives 0 remainder => NOT POSSIBLE
C. 9
Sum of all digits of 43 = 4+3 = 7 => Remainder of 43 by 9 = Remainder of 7 by 9 = 7
Sum of all digits of 91 = 9+1 = 10 => Remainder of 91 by 9 = Remainder of 10 by 9 = 1 => NOT POSSIBLE
D. 13
43 when divided by 13 gives 4 remainder
91 when divided by 13 gives 0 remainder => NOT POSSIBLE
E. 24
43 when divided by 24 gives 19 remainder
91 when divided by 24 gives 19 remainder
183 when divided by 24 gives 15 remainder=> NOT POSSIBLE
So, Answer will be A
Hope it helps!
Watch the following video to learn the Basics of Divisibility Rules
Watch the following video to learn the Basics of Remainders
A. 4
43, 91, 183 each when divided by 4 gives 3 remainder => POSSIBLE
B. 7
43 when divided by 7 gives 1 remainder
91 when divided by 7 gives 0 remainder => NOT POSSIBLE
C. 9
Sum of all digits of 43 = 4+3 = 7 => Remainder of 43 by 9 = Remainder of 7 by 9 = 7
Sum of all digits of 91 = 9+1 = 10 => Remainder of 91 by 9 = Remainder of 10 by 9 = 1 => NOT POSSIBLE
D. 13
43 when divided by 13 gives 4 remainder
91 when divided by 13 gives 0 remainder => NOT POSSIBLE
E. 24
43 when divided by 24 gives 19 remainder
91 when divided by 24 gives 19 remainder
183 when divided by 24 gives 15 remainder=> NOT POSSIBLE
So, Answer will be A
Hope it helps!
Watch the following video to learn the Basics of Divisibility Rules
Watch the following video to learn the Basics of Remainders
