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f=(-1,2)(, (1,5), , (3,-4)
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12 Jul 2021, 05:32
12 Jul 2021, 05:32
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66% (00:39) correct
33% (02:20) wrong based on 15 sessions
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\(f={(-1,2), (1,5), (3,-4)}\)
\(g={(-4,2), (-1,3), (2,-3)}\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
\(g={(-4,2), (-1,3), (2,-3)}\)
Quantity A |
Quantity B |
\( f(g(-1))\) |
\(g(f(-1))\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
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Re: f=(-1,2)(, (1,5), , (3,-4)
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13 Jul 2021, 20:42
13 Jul 2021, 20:42
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Carcass wrote:
\(f={(-1,2), (1,5), (3,-4)}\)
\(g={(-4,2), (-1,3), (2,-3)}\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
\(g={(-4,2), (-1,3), (2,-3)}\)
Quantity A |
Quantity B |
\( f(g(-1))\) |
\(g(f(-1))\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Col. A: \( f(g(-1))\)
Col. B: \( g(f(-1))\)
We have been given \(g\) at x = -1 is 3 and \(f\) at x = -1 is 2
So,
Col. A: \(f(3)\)
Col. B: \(g(2)\)
Also, \(f\) at x = 3 is -4 and \(g\) at x = 2 is -3
So,
Col. A: -4
Col. B: -3
Hence, option B
gmatclubot
Re: f=(-1,2)(, (1,5), , (3,-4) [#permalink]
13 Jul 2021, 20:42
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