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x and y are positive integers whose sum is 10 and 37 < 5x + 2y < 41
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12 Jul 2021, 05:34
12 Jul 2021, 05:34
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Question Stats:
72% (02:27) correct
27% (01:25) wrong based on 11 sessions
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x and y are positive integers whose sum is 10 and \(37 < 5x + 2y < 41\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
Quantity A |
Quantity B |
x |
y |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
x and y are positive integers whose sum is 10 and 37 < 5x + 2y < 41
[#permalink]
Updated on: 12 Jul 2021, 15:54
Updated on: 12 Jul 2021, 15:54
1
Let us think numbers are 1 and 9, 2 and 8, 3 and 7, 6 and 4 and 5 and 5. Now checking only 6,4 works for the inequalities.... Thats why ans A.
Posted from my mobile device
Posted from my mobile device
Originally posted by tusharstat43 on 12 Jul 2021, 05:44.
Last edited by tusharstat43 on 12 Jul 2021, 15:54, edited 1 time in total.
Last edited by tusharstat43 on 12 Jul 2021, 15:54, edited 1 time in total.
x and y are positive integers whose sum is 10 and 37 < 5x + 2y < 41
[#permalink]
12 Jul 2021, 07:30
12 Jul 2021, 07:30
1
\(x + y = 10\) & \(37 < 5x + 2y < 41\)
\(2x + 2y = 20\) _________(1)
\(37 < 3x + 2x + 2y < 41\)
By putting the value from eq(1)
\(37 < 3x + 20 < 41\)
\(17 < 3x < 21\)
\(x\) is an integer so only value that suffices this inequality is \(x = 6\) So \(y = 4\)
Qt A > Qt B
Answer A
\(2x + 2y = 20\) _________(1)
\(37 < 3x + 2x + 2y < 41\)
By putting the value from eq(1)
\(37 < 3x + 20 < 41\)
\(17 < 3x < 21\)
\(x\) is an integer so only value that suffices this inequality is \(x = 6\) So \(y = 4\)
Qt A > Qt B
Answer A
