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When positive integer x is divided by 20, the remainder is 8. What is
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12 Jul 2021, 05:55
12 Jul 2021, 05:55
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When positive integer x is divided by 20, the remainder is 8. What is the remainder when x is divided by 5?
A. 1
B. 3
C. 5
D. 8
E. Cannot be determined
A. 1
B. 3
C. 5
D. 8
E. Cannot be determined
Re: When positive integer x is divided by 20, the remainder is 8. What is
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12 Jul 2021, 07:40
12 Jul 2021, 07:40
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Positive integer \(x\) is divided by \(20\), the remainder is \(8\).
The lowest possible value for \(x\) will be \(28\)
When divided by \(5\), the remainder will be \(3\)
Answer B
The lowest possible value for \(x\) will be \(28\)
When divided by \(5\), the remainder will be \(3\)
Answer B
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Re: When positive integer x is divided by 20, the remainder is 8. What is
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12 Jul 2021, 08:25
12 Jul 2021, 08:25
Carcass wrote:
When positive integer x is divided by 20, the remainder is 8. What is the remainder when x is divided by 5?
A. 1
B. 3
C. 5
D. 8
E. Cannot be determined
A. 1
B. 3
C. 5
D. 8
E. Cannot be determined
There's a nice rule that say, "If N divided by D equals Q with remainder R, then N = DQ + R"
For example, since 17 divided by 5 equals 3 with remainder 2, then we can write 17 = (5)(3) + 2
Likewise, since 53 divided by 10 equals 5 with remainder 3, then we can write 53 = (10)(5) + 3
In this case, we aren't told how many times 20 divides into x, but this isn't a problem.
Let's just say that 20 divides into x k times.
In other words, x divided by 20 equals k with remainder 8
Applying the above rule, we can then say: x = 20k + 8 for some positive integer k
What is the remainder when x is divided by 5?
We know that: x = 20k + 8
Rewrite as: x = 20k + 5 + 3
And the factor to get: x = 5(4k + 1) + 3
So, we can see that x is 3 greater than some multiple of 5
This tells us that, if we divide x by 5, the remainder will be 3
Answer: B
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