GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
QOTD#22 Ben’s music album sold the number of copies as Regin
[#permalink]
30 Apr 2017, 14:02
30 Apr 2017, 14:02
1
Expert Reply
6
Bookmarks
00:00
Question Stats:
16% (00:46) correct
83% (01:44) wrong based on 55 sessions
Hide Show timer Statistics
Ben’s music album sold \(\frac{5}{6}\) the number of copies as Regina’s album. If Regina’s album sold at least 1,500 copies more than Ben’s album, how many copies of Ben’s album were sold?
Indicate all possible values.
A. 12,000
B. 11,244
C. 9,000
D. 6,500
E. 6,436
F. 4,225
Indicate all possible values.
A. 12,000
B. 11,244
C. 9,000
D. 6,500
E. 6,436
F. 4,225
Drill 4
Question: 9
Page: 322-323
Question: 9
Page: 322-323
Re: QOTD#22 Ben’s music album sold the number of copies as Regin
[#permalink]
04 May 2017, 01:14
04 May 2017, 01:14
2
Expert Reply
Explanation
To solve this question, plug in the answers. In choice (D), if Ben, B, sold 6500 copies and \(B = \frac{5}{6} \times R\) then \(6500 = \frac{5}{6} \times R\), so Regina, R, sold 7800 copies, thus giving a difference of 7800 − 6500 = 1300. Since this is too small, eliminate choices (D), (E), and (F) and try larger numbers.
In choice (C), if B = 9000, then \(9000 = \frac{5}{6} \times R\), so R = 10,800, thus giving 10,800 − 9000 = 1800; since this is bigger than 1500, keep choice (C).
In choice (B), if B = 11,244, then \(11,244 = \frac{5}{6} \times R\), so R = 13,492.8 copies; eliminate choice (B), as it is impossible to sell a fraction of an album.
In choice (A), if B = 12,000, then \(12,000 = \frac{5}{6} \times R\), so R = 14,400 and 14,400 − 12,000 = 2400. Since this is bigger than 1500, keep choice (A).
The correct answers are choices (A) and (C).
To solve this question, plug in the answers. In choice (D), if Ben, B, sold 6500 copies and \(B = \frac{5}{6} \times R\) then \(6500 = \frac{5}{6} \times R\), so Regina, R, sold 7800 copies, thus giving a difference of 7800 − 6500 = 1300. Since this is too small, eliminate choices (D), (E), and (F) and try larger numbers.
In choice (C), if B = 9000, then \(9000 = \frac{5}{6} \times R\), so R = 10,800, thus giving 10,800 − 9000 = 1800; since this is bigger than 1500, keep choice (C).
In choice (B), if B = 11,244, then \(11,244 = \frac{5}{6} \times R\), so R = 13,492.8 copies; eliminate choice (B), as it is impossible to sell a fraction of an album.
In choice (A), if B = 12,000, then \(12,000 = \frac{5}{6} \times R\), so R = 14,400 and 14,400 − 12,000 = 2400. Since this is bigger than 1500, keep choice (A).
The correct answers are choices (A) and (C).
Re: QOTD#22 Ben’s music album sold the number of copies as Regin
[#permalink]
15 Jun 2019, 09:22
15 Jun 2019, 09:22
Let's Rogina=6x, Ben=5x
where x= no. of albums, which must be a positive integer.
therefore, 6x-5x is greater than or equal to 1500.
or, x is greater than or equal to 1500, So Ben sells at least 5x or 5*1500 or 7500 albums .
by this logic, 5x =9000 as x is an integer when 9000/5;
similarly, 5x=11,244 is not possible as 11244/5 is not an integer.
the same goes valid with other options.
where x= no. of albums, which must be a positive integer.
therefore, 6x-5x is greater than or equal to 1500.
or, x is greater than or equal to 1500, So Ben sells at least 5x or 5*1500 or 7500 albums .
by this logic, 5x =9000 as x is an integer when 9000/5;
similarly, 5x=11,244 is not possible as 11244/5 is not an integer.
the same goes valid with other options.
