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(1/2-1/3)+(1/3-1/4)+(1/4+1/2)=
[#permalink]
16 Jul 2021, 04:48
16 Jul 2021, 04:48
Expert Reply
00:00
Question Stats:
63% (00:30) correct
36% (00:56) wrong based on 11 sessions
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\((\frac{1}{2}-\frac{1}{3})+(\frac{1}{3}-\frac{1}{4})+(\frac{1}{4}+\frac{1}{2})=\)
A. \(0\)
B. \(\frac{1}{4}\)
C. \(\frac{1}{2}\)
D. \(1\)
E. \(\frac{5}{4}\)
A. \(0\)
B. \(\frac{1}{4}\)
C. \(\frac{1}{2}\)
D. \(1\)
E. \(\frac{5}{4}\)
Re: (1/2-1/3)+(1/3-1/4)+(1/4+1/2)=
[#permalink]
16 Jul 2021, 09:12
16 Jul 2021, 09:12
2
\((\frac{1}{2}-\frac{1}{3})+(\frac{1}{3}-\frac{1}{4})+(\frac{1}{4}+\frac{1}{2})=\)
Let's open the brackets.
\(\frac{1}{2}\) - \(\frac{1}{3}\) + \(\frac{1}{3}\) - \(\frac{1}{4}\) + \(\frac{1}{4}\) + \(\frac{1}{2}\)
\(\frac{1}{2}\) + \(\frac{1}{2}\) \(= 1\)
Answer D
Let's open the brackets.
\(\frac{1}{2}\) - \(\frac{1}{3}\) + \(\frac{1}{3}\) - \(\frac{1}{4}\) + \(\frac{1}{4}\) + \(\frac{1}{2}\)
\(\frac{1}{2}\) + \(\frac{1}{2}\) \(= 1\)
Answer D
gmatclubot
Re: (1/2-1/3)+(1/3-1/4)+(1/4+1/2)= [#permalink]
16 Jul 2021, 09:12
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