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Re: The vertices of square S have coordinates [#permalink]
Can someone answer this?
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Re: The vertices of square S have coordinates [#permalink]
HarveyKlaus wrote:
The vertices of square S have coordinates (-1,-2), (-1,1), (2,1), and (2,-2) respectively. What are the coordinates of the point where the diagonals of S intersect?

a) (1/2, 1/2)
b) (1/2, -1/2)
c) (3/2, 1/2)
d) (3/2, -1/2)
e) (underoot3/2, 1/2)


When we sketch the square on the coordinate plane, we get the following:
Image

Notice that the intersection point of the two diagonals will be the MIDPOINT of the red line segment (or the green line segment. It makes no difference)

The midpoint of the red line segment \(= (\frac{(-1) + 2}{2}, \frac{(-2) + 1}{2})\)

\(= (\frac{1}{2}, \frac{-1}{2})\)

Answer: B

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Re: The vertices of square S have coordinates [#permalink]
The midpoint of a line (or the intersection) can be calculated as x1+x2/2, y1+y2/2

To calculate it:

Add both "x" coordinates, divide by 2
Add both "y" coordinates, divide by 2

https://www.mathsisfun.com/algebra/line-midpoint.html
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Re: The vertices of square S have coordinates [#permalink]
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