Answer=A
I used a^2+b^2=C^2=100
if we use z=5 z^2=25 the rest is 75 there is nothing square smth gives u 75, therefore, it could be less than Z or greater than Z not equal to 5. i tried Z=4 but it is not working then i tried z=6 and it works thereafter, it should be greater than Z which is Z=6 Z^2=36
b=8 , b^2=64 , Z^2+b^2= 36+64=100
Answer A

Answer=A
I used a^2+b^2=C^2=100
if we use z=5 z^2=25 the rest is 75 there is nothing square smth gives u 75, therefore, it could be less than Z or greater than Z not equal to 5. I tried Z=4 but it is not working then I tried z=6 and it works thereafter, it should be greater than Z which is Z=6 Z^2=36
b=8 , b^2=64 , Z^2+b^2= 36+64=100
Answer A

why can't we use the triplet property to solve this question? for example 3x,4y,5z!

Hi there!

Just to clarify x and y are the measure of the angles i.e the degrees and not the length of the side. Although I agree that we can use pythagoras theorem, but that will deviate us from the information given y>2z this information is given for some purpose. This is the only information that derives us to the correct answer for
eg. If I use pythagoras the sides can be 6, 8 & 10 or \(5\sqrt{2}, 5\sqrt{2}\), 10

thanks for your quick response and for clearing my doubt.

yes, you're right it should be in the whole x by mistake I wrote x,y,z.



In both the cases z is greater than 5. But we do not surely know that y>2x. When we use this information, we already know that one angle is 90 the other two will sum upto 90 and as y>2x, y>60 and x<30 and z<5.


And yes good to know: Whenever we use pythogaras theorem the constant are same and not distinct i.e 3x, 4x & 5x and not 3x, 4y & 5z!!!!

Let me know if I can help further!

Hope this helps!