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(2x+3y)^2
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22 Jul 2021, 04:48
22 Jul 2021, 04:48
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Question Stats:
61% (01:03) correct
38% (00:25) wrong based on 13 sessions
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Quantity A |
Quantity B |
\((2x+3y)^2\) |
\(4x^2+6xy+9y^2\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
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Given Kudos: 136
(2x+3y)^2
[#permalink]
22 Jul 2021, 05:07
22 Jul 2021, 05:07
1
Carcass wrote:
Quantity A |
Quantity B |
\((2x+3y)^2\) |
\(4x^2+6xy+9y^2\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
Use FOIL to expand and simplify Quantity A:
QUANTITY A: \((2x+3y)^2=(2x+3y)(2x+3y)=4x^2+6xy+6xy+9y^2=4x^2+12xy+9y^2\)
QUANTITY B: \(4x^2+6xy+9y^2\)
Subtract \(4x^2\) and \(9y^2\) from both quantities to get:
QUANTITY A: \(12xy\)
QUANTITY B: \(6xy\)
Subtract \(6xy\) from both quantities to get:
QUANTITY A: \(6xy\)
QUANTITY B: \(0\)
If \(x=0\) and \(y=0\), but then the two quantities are equal
If \(x=1\) and \(y=1\), but then Quantity A is greater
If \(x=-1\) and \(y=1\), but then Quantity B is greater
Answer: D
gmatclubot
(2x+3y)^2 [#permalink]
22 Jul 2021, 05:07
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