Carcass wrote:
A membership list of 620 people shows that 31 of them have first and last names that begin with the same letter. If a person is selected at random from the list, what is the probability that the person’s first and last names do not begin with the same letter?
(A) 0.05
(B) 0.25
(C) 0.50
(D) 0.75
(E) 0.95
P(first&last name the same letter)=31/620=31/(31*20)=1/20.
P(first&last name not the same letter) = 1 - P(first&last name the same letter) according to complement rule
1 - 0.05 = 0.95. Answer is
E.
It's easy, busy entry