Last visit was: 21 Nov 2024, 22:00 It is currently 21 Nov 2024, 22:00
Decision Tracker
My Rewards
New comers' posts
New posts
Unanswered

Close

GRE Prep Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GRE score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Go to My Error Log Learn more
Close

Request Expert Reply

Confirm Cancel
PREVIOUS TOPIC
NEXT TOPIC

Set A is given as A = {4, 5, 5, 5, 5, 5, 5, 5, 6, 7, 11, 12, 16}

Tags :
Find Similar Topics  About  Add a Tag

Show Tags
Hide Tags

User avatar
G
motion2020
Retired Moderator
Joined: 19 Nov 2020
Posts: 326
Own Kudos [?]: 373 [2]
Given Kudos: 64
GRE 1: Q160 V152
Send PM
Set A is given as A = {4, 5, 5, 5, 5, 5, 5, 5, 6, 7, 11, 12, 16} [#permalink] New post   Updated on: 29 Jul 2021, 11:28
2
Bookmarks
00:00

Question Stats:

52% (02:20) correct 47% (01:21) wrong based on 23 sessions

Hide Show timer Statistics

Set A is given as A = {4, 5, 5, 5, 5, 5, 5, 5, 6, 7, 11, 12, 16}
Set B includes numbers the same as in the set A with 3 subtracted from each number and then multipled by 1.5



Quantity A
Quantity B
7
Arithmetic average of the set B


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
ShowHide Answer
Official Answer
A

Originally posted by motion2020 on 29 Jul 2021, 10:04.
Last edited by GeminiHeat on 29 Jul 2021, 11:28, edited 2 times in total.
Formatted
User avatar
D
Carcass
Verbal Expert
Joined: 18 Apr 2015
Posts: 30003
Own Kudos [?]: 36341 [0]
Given Kudos: 25927
Send PM
Re: Set A is given as A = {4, 5, 5, 5, 5, 5, 5, 5, 6, 7, 11, 12, 16} [#permalink] New post   29 Jul 2021, 10:13
Expert Reply
See here how to create the two quantities. Quite easy https://gre.myprepclub.com/forum/how-to-po ... 12752.html

Also add always the 4 answer choices

Thank you
User avatar
G
motion2020
Retired Moderator
Joined: 19 Nov 2020
Posts: 326
Own Kudos [?]: 373 [0]
Given Kudos: 64
GRE 1: Q160 V152
Send PM
Re: Set A is given as A = {4, 5, 5, 5, 5, 5, 5, 5, 6, 7, 11, 12, 16} [#permalink] New post   29 Jul 2021, 10:39
Carcass wrote:
See here how to create the two quantities. Quite easy https://gre.myprepclub.com/forum/how-to-po ... 12752.html

Also add always the 4 answer choices

Thank you

thanks!
User avatar
G
motion2020
Retired Moderator
Joined: 19 Nov 2020
Posts: 326
Own Kudos [?]: 373 [0]
Given Kudos: 64
GRE 1: Q160 V152
Send PM
Set A is given as A = {4, 5, 5, 5, 5, 5, 5, 5, 6, 7, 11, 12, 16} [#permalink] New post   02 Aug 2021, 02:43
This question has not been answered yet..
User avatar
P
GreenlightTestPrep
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Own Kudos [?]: 12196 [2]
Given Kudos: 136
Send PM

Top Member of the Month
Re: Set A is given as A = {4, 5, 5, 5, 5, 5, 5, 5, 6, 7, 11, 12, 16} [#permalink] New post   02 Aug 2021, 06:10
1
1
Bookmarks
motion2020 wrote:
Set A is given as A = {4, 5, 5, 5, 5, 5, 5, 5, 6, 7, 11, 12, 16}
Set B includes numbers the same as in the set A with 3 subtracted from each number and then multiplied by 1.5



Quantity A
Quantity B
7
Arithmetic average of the set B


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.


Average of set A \(= \frac{4+5+5+5+5+5+5+5+6+7+11+12+16}{13} = 7\)

If we subtract 3 from each value, then the new average (arithmetic mean) = 7 - 3 = 4

If we now multiply each value by 1,5, the new average = (4)(1.5) = 6

So, the average of Set B = 6

So we get:
QUANTITY A: 7
QUANTITY B: 6

Answer: A
User avatar
G
motion2020
Retired Moderator
Joined: 19 Nov 2020
Posts: 326
Own Kudos [?]: 373 [0]
Given Kudos: 64
GRE 1: Q160 V152
Send PM
Set A is given as A = {4, 5, 5, 5, 5, 5, 5, 5, 6, 7, 11, 12, 16} [#permalink] New post   02 Aug 2021, 09:33
and morale of this question is that adding and multiplying or dividing the mean (average) by constant should change the mean (new mean is obtained) by that constant's addition, multiplication or division
GreenlightTestPrep wrote:
motion2020 wrote:
Set A is given as A = {4, 5, 5, 5, 5, 5, 5, 5, 6, 7, 11, 12, 16}
Set B includes numbers the same as in the set A with 3 subtracted from each number and then multiplied by 1.5



Quantity A
Quantity B
7
Arithmetic average of the set B


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.


Average of set A \(= \frac{4+5+5+5+5+5+5+5+6+7+11+12+16}{13} = 7\)

If we subtract 3 from each value, then the new average (arithmetic mean) = 7 - 3 = 4

If we now multiply each value by 1,5, the new average = (4)(1.5) = 6

So, the average of Set B = 6

So we get:
QUANTITY A: 7
QUANTITY B: 6

Answer: A
Prep Club for GRE Bot
gmatclubot
Set A is given as A = {4, 5, 5, 5, 5, 5, 5, 5, 6, 7, 11, 12, 16} [#permalink]
02 Aug 2021, 09:33
Moderators:
adewale223
GRE Instructor
84 posts
bronaugust
GRE Forum Moderator
37 posts
BrushMyQuant
Moderator
1111 posts
VibhuAnurag
GRE Instructor
234 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne

Main navigation

Partners

GRE Resources

www.ets.org/gre | About | Terms and Conditions and Privacy Policy | Prep Club for GRE Rules | Contact