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Arithmetic and Fractions
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18 May 2017, 02:15
18 May 2017, 02:15
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Question Stats:
57% (00:15) correct
42% (00:48) wrong based on 7 sessions
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A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Re: Arithmetic and Fractions
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18 May 2017, 07:16
18 May 2017, 07:16
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Expert Reply
Assume \(W = 1\). and \(z= -1\)
Quanity A= \(\frac{W+z}{W-z}=\frac{1 - 1}{1 - (-1)}= 0\)
Quanity B= \(\frac{W+z}{-W+z}=\frac{1 - 1}{-1 -1)}=0\)
The quanities are equal.
Now assume \(W = 1\). and \(z= -2\)
Quanity A= \(\frac{W+z}{W-z}=\frac{1 - 2}{1 - (-2)}= \frac{-1}{3}\)
Quanity B= \(\frac{W+z}{-W+z}=\frac{1 - 2}{-2 -1}=\frac{1}{3}\)
Quanitity B is greater. Clearly a relationship cannot be determined.
Hence option D is correct!
Quanity A= \(\frac{W+z}{W-z}=\frac{1 - 1}{1 - (-1)}= 0\)
Quanity B= \(\frac{W+z}{-W+z}=\frac{1 - 1}{-1 -1)}=0\)
The quanities are equal.
Now assume \(W = 1\). and \(z= -2\)
Quanity A= \(\frac{W+z}{W-z}=\frac{1 - 2}{1 - (-2)}= \frac{-1}{3}\)
Quanity B= \(\frac{W+z}{-W+z}=\frac{1 - 2}{-2 -1}=\frac{1}{3}\)
Quanitity B is greater. Clearly a relationship cannot be determined.
Hence option D is correct!
Re: Arithmetic and Fractions
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08 Jul 2021, 06:44
08 Jul 2021, 06:44
1
Hello from the GRE Prep Club BumpBot!
Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
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Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
