Last visit was: 21 Nov 2024, 12:27 It is currently 21 Nov 2024, 12:27
Decision Tracker
My Rewards
New comers' posts
New posts
Unanswered

Close

GRE Prep Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GRE score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Go to My Error Log Learn more
Close

Request Expert Reply

Confirm Cancel
PREVIOUS TOPIC
NEXT TOPIC

Jim is twice as old as Stephanie, who, four years ago, was three times

Tags :
Find Similar Topics  About  Add a Tag

Show Tags
Hide Tags

User avatar
D
Carcass
Verbal Expert
Joined: 18 Apr 2015
Posts: 30002
Own Kudos [?]: 36336 [3]
Given Kudos: 25926
Send PM
Jim is twice as old as Stephanie, who, four years ago, was three times [#permalink] New post   13 Apr 2021, 05:51
Expert Reply
3
Bookmarks
00:00

Question Stats:

70% (02:20) correct 29% (02:29) wrong based on 37 sessions

Hide Show timer Statistics

Jim is twice as old as Stephanie, who, four years ago, was three times as old as Kate. If, five years from now, the sum of their ages will be 51, how old is Stephanie ?

A. 6
B. 10
C. 14
D. 20
E. 24

Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
ShowHide Answer
Official Answer
B
User avatar
P
GreenlightTestPrep
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Own Kudos [?]: 12196 [1]
Given Kudos: 136
Send PM

Top Member of the Month
Re: Jim is twice as old as Stephanie, who, four years ago, was three times [#permalink] New post   13 Apr 2021, 05:58
1
Carcass wrote:
Jim is twice as old as Stephanie, who, four years ago, was three times as old as Kate. If, five years from now, the sum of their ages will be 51, how old is Stephanie ?

A. 6
B. 10
C. 14
D. 20
E. 24

Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book


Let's solve this question by testing the answer choices, so . . .

Test answer choice A
If Stephanie is PRESENTLY 6 years old, then JIM is PRESENTLY 20 years old
FOUR YEARS AGO, Stephanie as 2 years old, which means Kate was 2/3 years old FOUR YEARS AGO
Stop!!
Since it's highly unlikely that Kate's age is a fraction, we can move on


Test answer choice B
If Stephanie is PRESENTLY 10 years old, then JIM is PRESENTLY 20 years old
FOUR YEARS AGO, Stephanie as 6 years old, which means Kate was 2 years old FOUR YEARS AGO
So, FIVE YEARS FROM NOW, Stephanie will be 15, Jim will be 25, and Kate will be 11
Sum of the ages = 15 + 25 + 11 = 51
It works!!

Answer: B

Cheers,
Brent
avatar
B
mrk9414
Intern
Intern
Joined: 19 Oct 2020
Posts: 33
Own Kudos [?]: 41 [0]
Given Kudos: 41
Send PM
Re: Jim is twice as old as Stephanie, who, four years ago, was three times [#permalink] New post   01 Aug 2021, 07:35
GreenlightTestPrep wrote:
Carcass wrote:
Jim is twice as old as Stephanie, who, four years ago, was three times as old as Kate. If, five years from now, the sum of their ages will be 51, how old is Stephanie ?

A. 6
B. 10
C. 14
D. 20
E. 24

Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book


Let's solve this question by testing the answer choices, so . . .

Test answer choice A
If Stephanie is PRESENTLY 6 years old, then JIM is PRESENTLY 20 years old
FOUR YEARS AGO, Stephanie as 2 years old, which means Kate was 2/3 years old FOUR YEARS AGO
Stop!!
Since it's highly unlikely that Kate's age is a fraction, we can move on


Test answer choice B
If Stephanie is PRESENTLY 10 years old, then JIM is PRESENTLY 20 years old
FOUR YEARS AGO, Stephanie as 6 years old, which means Kate was 2 years old FOUR YEARS AGO
So, FIVE YEARS FROM NOW, Stephanie will be 15, Jim will be 25, and Kate will be 11
Sum of the ages = 15 + 25 + 11 = 51
It works!!

Answer: B

Cheers,
Brent


can you please explain to me through solving method so that I can understand behind logic
User avatar
D
Carcass
Verbal Expert
Joined: 18 Apr 2015
Posts: 30002
Own Kudos [?]: 36336 [0]
Given Kudos: 25926
Send PM
Jim is twice as old as Stephanie, who, four years ago, was three times [#permalink] New post   01 Aug 2021, 07:52
Expert Reply
Translate

\(J=2S\)

\(S-4=3K\)

\(J+5+S+5+K+5=51\)

\(J+S+K+15=51\)

\(J+S+K=36\)

Substitute

\(2S+S+K=36\)

\(3S+\frac{S-4}{3}=36\)

\(9S+S-4=108\)

\(10S=112\)

\(S=11.3\)

So the closest option must be B which is equal to 10
User avatar
P
GreenlightTestPrep
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Own Kudos [?]: 12196 [3]
Given Kudos: 136
Send PM

Top Member of the Month
Re: Jim is twice as old as Stephanie, who, four years ago, was three times [#permalink] New post   01 Aug 2021, 07:56
2
1
Bookmarks
Carcass wrote:
Jim is twice as old as Stephanie, who, four years ago, was three times as old as Kate. If, five years from now, the sum of their ages will be 51, how old is Stephanie ?

A. 6
B. 10
C. 14
D. 20
E. 24

Here's an algebraic approach.

Let x = Stephanie's present age.

James is twice as old as Stephanie
So 2x = James' present age.

4 years ago, Stephanie's was 3 times as old as Kate
In other words, 4 years ago, Kate's age was 1/3 of Stephanie's age.
4 years ago, Stephanie'sage was x-4, so Kate's age 4 years ago, was (x-4)/3
So, Kate's present age = (x-4)/3 + 4

In 5 years . . .
Stephanie's age = x + 5
James' age = 2x + 5
Kate's age = (x-4)/3 + 4 + 5

5 years from now, the sum of their ages will be 51
So (x + 5) + (2x + 5) + (x-4)/3 + 4 + 5 = 51
Simplify: 3x + (x-4)/3 + 19 = 51
Subtract 19 from both sides: 3x + (x-4)/3 = 32
Multiply both sides by 3: 9x + (x-4) = 96
Solve . . . x = 10

Answer: B
User avatar
D
rx10
Retired Moderator
Joined: 02 Dec 2020
Posts: 1831
Own Kudos [?]: 2146 [2]
Given Kudos: 140
GRE 1: Q168 V157

GRE 2: Q167 V161
Send PM
Re: Jim is twice as old as Stephanie, who, four years ago, was three times [#permalink] New post   01 Aug 2021, 07:57
2
Jim is twice as old as Stephanie

\(J = 2S\)

Four years ago, Stephanie was three times as old as Kate

\(S-4 = 3(K-4)\)

\(S = 3K - 8\)

five years from now, the sum of their ages will be \(51\)

\(J + 5 + S + 5 + K + 5 = 51\)

\(2S + S + K = 36\)

\(3(3K-8) + K = 36\)

\(10K = 60\)

\(K = 6\)

\(S = 10\)

mrk9414 wrote:
can you please explain to me through solving method so that I can understand behind logic
User avatar
D
Carcass
Verbal Expert
Joined: 18 Apr 2015
Posts: 30002
Own Kudos [?]: 36336 [1]
Given Kudos: 25926
Send PM
Jim is twice as old as Stephanie, who, four years ago, was three times [#permalink] New post   01 Aug 2021, 08:09
1
Expert Reply
OMG

One time I attempt a question via algebra......another 3 top-notch explanations.......

Like honey bees :P

I made a mistake balanced the equation \(S−4=3(K−4)\)

:roll:
User avatar
G
motion2020
Retired Moderator
Joined: 19 Nov 2020
Posts: 326
Own Kudos [?]: 373 [1]
Given Kudos: 64
GRE 1: Q160 V152
Send PM
Jim is twice as old as Stephanie, who, four years ago, was three times [#permalink] New post   01 Aug 2021, 09:52
1
J=Jim, S=Stephanie and K=Kate.
Now ----> J=2S
4 years back ----> S-4=3(K-4)
5 years forward ----> J+S+K+3*5=51

Solve for S by substitution/combination of three equations

J+S+K=36 AND 2S+S+(S+8)/3=36 ----> 3S*3+S+8=36*3, 10S=108-8, S=10, Answer is B
S-4=3K-12, K=(S+8)/3

Carcass wrote:
Jim is twice as old as Stephanie, who, four years ago, was three times as old as Kate. If, five years from now, the sum of their ages will be 51, how old is Stephanie ?

A. 6
B. 10
C. 14
D. 20
E. 24

Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
avatar
B
rile
Intern
Intern
Joined: 11 Jul 2022
Posts: 1
Own Kudos [?]: 0 [0]
Given Kudos: 19
Re: Jim is twice as old as Stephanie, who, four years ago, was three times [#permalink] New post   16 Jul 2022, 07:37
Carcass wrote:
Translate

\(J=2S\)

\(S-4=3K\)

\(J+5+S+5+K+5=51\)

\(J+S+K+15=51\)

\(J+S+K=36\)

Substitute

\(2S+S+K=36\)

\(3S+\frac{S-4}{3}=36\)

\(9S+S-4=108\)

\(10S=112\)

\(S=11.3\)

So the closest option must be B which is equal to 10


In the S-4=3K
we will need to subtract 4 from K as well,
so the modified eq will be
S-4= 3K-4
which will yield exact 10 for S
avatar
B
SivhHarish
Manager
Manager
Joined: 01 Apr 2022
Posts: 65
Own Kudos [?]: 15 [0]
Given Kudos: 79
Send PM
Re: Jim is twice as old as Stephanie, who, four years ago, was three times [#permalink] New post   17 Jul 2022, 04:59
Quote:
Test answer choice A
If Stephanie is PRESENTLY 6 years old, then JIM is PRESENTLY 20 years old
FOUR YEARS AGO, Stephanie as 2 years old, which means Kate was 2/3 years old FOUR YEARS AGO
Stop!!
Since it's highly unlikely that Kate's age is a fraction, we can move on


Sir, I think Jim's present age is an error here. Please check it out!
User avatar
bumpbot
GRE Prep Club Legend
GRE Prep Club Legend
Joined: 07 Jan 2021
Posts: 5030
Own Kudos [?]: 74 [0]
Given Kudos: 0
Send PM
Re: Jim is twice as old as Stephanie, who, four years ago, was three times [#permalink] New post   13 Nov 2024, 01:06
Hello from the GRE Prep Club BumpBot!

Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Prep Club for GRE Bot
gmatclubot
Re: Jim is twice as old as Stephanie, who, four years ago, was three times [#permalink]
13 Nov 2024, 01:06
Moderators:
adewale223
GRE Instructor
83 posts
bronaugust
GRE Forum Moderator
37 posts
BrushMyQuant
Moderator
1111 posts
VibhuAnurag
GRE Instructor
234 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne

Main navigation

Partners

GRE Resources

www.ets.org/gre | About | Terms and Conditions and Privacy Policy | Prep Club for GRE Rules | Contact