GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 2506
Given Kudos: 1055
GPA: 3.39
Matt earned a $1,000 commission on a big sale, raising his average com
[#permalink]
02 Aug 2021, 01:09
02 Aug 2021, 01:09
Expert Reply
3
Bookmarks
00:00
Question Stats:
75% (02:07) correct
25% (01:36) wrong based on 12 sessions
Hide Show timer Statistics
Matt earned a $1,000 commission on a big sale, raising his average commission by $150. If Matt’s new average commission is $400, how many sales has he made?
A. 3
B. 4
C. 5
D. 6
E. 7
A. 3
B. 4
C. 5
D. 6
E. 7
Retired Moderator
Joined: 16 Apr 2020
Status:Founder & Quant Trainer
Affiliations: Prepster Education
Posts: 1546
Given Kudos: 172
Location: India
WE:Education (Education)
Re: Matt earned a $1,000 commission on a big sale, raising his average com
[#permalink]
03 Aug 2021, 07:49
03 Aug 2021, 07:49
1
1
Bookmarks
GeminiHeat wrote:
Matt earned a $1,000 commission on a big sale, raising his average commission by $150. If Matt’s new average commission is $400, how many sales has he made?
A. 3
B. 4
C. 5
D. 6
E. 7
A. 3
B. 4
C. 5
D. 6
E. 7
Let,
Sum of his commission be \(S\)
Number of sales be \(n\)
Average be \(X\)
\(X = \frac{S}{n}\)
After a \($1000\) commission,
\(\frac{S + 1000}{n + 1} = X + 150 = 400\)
i.e. \(X = 400 - 150 = 250\)
So, \(S = 250n\) and also \(S = 400(n + 1) - 1000\)
\(250n = 400(n + 1) - 1000\)
\(250n = 400n + 400 - 1000\)
\(150n = 600\)
\(n = 4\)
Total sales = \((n + 1) = 5\)
Hence, option C
gmatclubot
Re: Matt earned a $1,000 commission on a big sale, raising his average com [#permalink]
03 Aug 2021, 07:49
Moderators:
