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GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 2506
Given Kudos: 1055
GPA: 3.39
In the figure above, a right triangle is located entirely inside a squ
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02 Aug 2021, 01:45
02 Aug 2021, 01:45
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In the figure above, a right triangle is located entirely inside a square with side length of 6. If all three side lengths of the right triangle are integers, what fraction of the square is shaded?
A. 1/6
B. 1/4
C. \(\frac{1}{\sqrt{3}}\)
D. \(\frac{\sqrt{2}}{3}\)
E. It cannot be determined
Retired Moderator
Joined: 19 Nov 2020
Posts: 326
Given Kudos: 64
GRE 1: Q160 V152
Re: In the figure above, a right triangle is located entirely inside a squ
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02 Aug 2021, 04:03
02 Aug 2021, 04:03
is this a hard one? 
triangle is 3-4-5 and area=3*4/2=6 (shaded area)
fraction of the square shaded=6/36=1/6. Answer is A
In the figure above, a right triangle is located entirely inside a square with side length of 6. If all three side lengths of the right triangle are integers, what fraction of the square is shaded?
A. 1/6
B. 1/4
C. \(\frac{1}{\sqrt{3}}\)
D. \(\frac{\sqrt{2}}{3}\)
E. It cannot be determined
triangle is 3-4-5 and area=3*4/2=6 (shaded area)
fraction of the square shaded=6/36=1/6. Answer is A
GeminiHeat wrote:
In the figure above, a right triangle is located entirely inside a square with side length of 6. If all three side lengths of the right triangle are integers, what fraction of the square is shaded?
A. 1/6
B. 1/4
C. \(\frac{1}{\sqrt{3}}\)
D. \(\frac{\sqrt{2}}{3}\)
E. It cannot be determined
Re: In the figure above, a right triangle is located entirely inside a squ
[#permalink]
02 Aug 2021, 04:08
02 Aug 2021, 04:08
Expert Reply
motion2020 wrote:
is this a hard one?
triangle is 3-4-5 and area=3*4/2=6 (shaded area)
fraction of the square shaded=6/36=1/6. Answer is A
In the figure above, a right triangle is located entirely inside a square with side length of 6. If all three side lengths of the right triangle are integers, what fraction of the square is shaded?
A. 1/6
B. 1/4
C. \(\frac{1}{\sqrt{3}}\)
D. \(\frac{\sqrt{2}}{3}\)
E. It cannot be determined
triangle is 3-4-5 and area=3*4/2=6 (shaded area)
fraction of the square shaded=6/36=1/6. Answer is A
GeminiHeat wrote:
In the figure above, a right triangle is located entirely inside a square with side length of 6. If all three side lengths of the right triangle are integers, what fraction of the square is shaded?
A. 1/6
B. 1/4
C. \(\frac{1}{\sqrt{3}}\)
D. \(\frac{\sqrt{2}}{3}\)
E. It cannot be determined
I know you said that for the good
However, a question when is labeled "hard" is so having in mind the average students.
Those questions that are hard for me for Bunuel are easy. So in the upper range is a matter of perspective, sort of.
Thank you Sir
Regards
