Of all integers only those ending with 1 and 9 result in squred integer's unit=1.
Given 1 and 9 or N1 and N9 are added by 1, the squared digits will ending in 0 for 9 or N9.
When added by 2, the unit's digit of N9 will be 1 for the squared integer results in unit's digit of 1 too. Answer is
ACarcass wrote:
If \(k\) is a positive integer, and if the units’ digit of \(k^2\) is 1 and the units' digit of \((k+1)^2\) is 0, what is the units' digit of \((k+2)^2\)?
(A) 1
(B) 3
(C) 5
(D) 7
(E) 9