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If the average (arithmetic mean) of u w x,y and z is 12.3, a
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22 May 2017, 01:08
22 May 2017, 01:08
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Question Stats:
88% (01:15) correct
11% (01:13) wrong based on 72 sessions
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If the average (arithmetic mean) of v, w, x, y and z is 12.3, and the average of v and w is 45.6, what is the average of x, y, and z?
Enter your value
Show: :: OA
-9.9
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Re: If the average (arithmetic mean) of u w x,y and z is 12.3, a
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22 May 2017, 15:19
22 May 2017, 15:19
2
Carcass wrote:
If the average (arithmetic mean) of v, w, x, y and z is 12.3, and the average of v and w is 45.6, what is the average of x, y, and z?
Enter your value
Show: :: OA
-9.9
The average (arithmetic mean) of v, w, x, y and z is 12.3
So, (v + w + x + y + z)/5 = 12.3
Multiply both sides by 5 to get: v + w + x + y + z = 61.5
The average of v and w is 45.6
So, (v + w)/2 = 45.6
Multiply both sides by 2 to get: v + w = 91.2
What is the average of x, y, and z?
We need the sum of x, y, and z
We have two equations:
v + w + x + y + z = 61.5
v + w = 91.2
Subtract the bottom equation FROM the top equation to get: x + y + z = -29.7
Divide both sides by 3 to get: (x + y + z) = (-29.7)/3 = -9.9
Answer:
Show: ::
-9.9
RELATED VIDEO
Re: If the average (arithmetic mean) of u w x,y and z is 12.3, a
[#permalink]
20 Feb 2023, 04:17
20 Feb 2023, 04:17
v+w+x+y+z=61.5
v+w=91.2
so,x+y+z=-29.7
so,average=-29.7/3=-9.9
v+w=91.2
so,x+y+z=-29.7
so,average=-29.7/3=-9.9
