Retired Moderator
Joined: 07 Jun 2014
Posts: 4815
Given Kudos: 0
WE:Business Development (Energy and Utilities)
Re: Claudette traveled the first of a 60-mile trip at 20 miles p
[#permalink]
15 Jul 2018, 02:52
Explanation
First, figure out how long it took Claudette to travel 60 miles under the actual conditions.
The first leg of the trip was \(\frac{2}{3}\)of 60 miles, or 40 miles.
To travel 40 miles at a rate of 20 miles per hour, Claudette spent \(\frac{40}{20}= 2\)hours = 120 minutes.
The second leg of the trip was the remaining 60 – 40 = 20 miles. To travel that distance at a rate of 30 miles per hour, Claudette spent \(\frac{20}{30}= \frac{2}{3}\)hours= 40 minutes.
In total, Claudette traveled for 120 + 40 = 160 minutes. Now consider the hypothetical trip. If Claudette had traveled the whole distance of 60 miles at 20
miles per hour, the trip would have taken \(\frac{180}{20}= 3\)hours= 180 minutes.
Finally, compare the two trips. The real trip took 160 minutes, so the hypothetical trip would have taken 180 – 160 = 20 minutes longer.