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If the operation # is defined for all f and g by the equation
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05 Aug 2021, 10:32
05 Aug 2021, 10:32
Expert Reply
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Question Stats:
92% (00:40) correct
7% (00:40) wrong based on 26 sessions
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If the operation # is defined for all f and g by the equation \(f # g = \frac{f^2g}{2}\), then 3#(-1#-2)=
A. -9/2
B. -1
C. 4
D. 9/2
E. 81/4
A. -9/2
B. -1
C. 4
D. 9/2
E. 81/4
Re: If the operation # is defined for all f and g by the equation
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05 Aug 2021, 19:36
05 Aug 2021, 19:36
1
\(f # g = \frac{f^2g}{2}\)
(-1#-2) = \(\frac{(-1)^2 * (-2)}{2} = -1 \)
3#-1 \(= \frac{3^2 * (-1)}{2} = \frac{-9}{2}\)
Answer A
(-1#-2) = \(\frac{(-1)^2 * (-2)}{2} = -1 \)
3#-1 \(= \frac{3^2 * (-1)}{2} = \frac{-9}{2}\)
Answer A
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Re: If the operation # is defined for all f and g by the equation
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15 Jan 2022, 10:15
15 Jan 2022, 10:15
1
Given that \(f \# g = \frac{f^2g}{2}\) and we need to find the value of 3#(-1#-2)
To find -1#-2 we need to compare -1#-2 with f#g and we what is before the # and what is after
=> f = -1 and g = -2
=> to find the value of -1#-2 we need to replace f with -1 and g with -2 in \(f \# g = \frac{f^2g}{2}\)
=> \(-1 \# -2 = \frac{(-1)^2*(-2)}{2}\) = 1*-1 = -1
=> 3#(-1#-2) = 3#-1 = \(\frac{3^2*(-1)}{2}\) = \(\frac{-9}{2}\)
So, Answer will be A
Hope it helps!
Watch the following video to learn the Basics of Functions and Custom Characters
To find -1#-2 we need to compare -1#-2 with f#g and we what is before the # and what is after
=> f = -1 and g = -2
=> to find the value of -1#-2 we need to replace f with -1 and g with -2 in \(f \# g = \frac{f^2g}{2}\)
=> \(-1 \# -2 = \frac{(-1)^2*(-2)}{2}\) = 1*-1 = -1
=> 3#(-1#-2) = 3#-1 = \(\frac{3^2*(-1)}{2}\) = \(\frac{-9}{2}\)
So, Answer will be A
Hope it helps!
Watch the following video to learn the Basics of Functions and Custom Characters
