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If 4^x2^y=16 and 3^x3^y=27, then (x,y)=
[#permalink]
05 Aug 2021, 10:35
05 Aug 2021, 10:35
Expert Reply
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Question Stats:
93% (00:52) correct
6% (02:05) wrong based on 31 sessions
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If \(4^x2^y=16\) and \(3^x3^y=27\), then \((x,y)=\)
(A) (1, 2)
(B) (2, 1)
(C) (1, 1)
(D) (2, 2)
(E) (1, 3)
(A) (1, 2)
(B) (2, 1)
(C) (1, 1)
(D) (2, 2)
(E) (1, 3)
Re: If 4^x2^y=16 and 3^x3^y=27, then (x,y)=
[#permalink]
05 Aug 2021, 19:39
05 Aug 2021, 19:39
1
\(4^x2^y=16\) & \(3^x3^y=27\)
Try values from the options.
The only value that suffices both is (x , y) = (1 , 2)
Answer A
Try values from the options.
The only value that suffices both is (x , y) = (1 , 2)
Answer A
Re: If 4^x2^y=16 and 3^x3^y=27, then (x,y)=
[#permalink]
23 Aug 2021, 05:21
23 Aug 2021, 05:21
Should have written, (x,y) rather than x.y. I thought we had to multiply x*y.
