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If x > y, increasing the original price of an item by x% and then decr
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05 Aug 2021, 11:22
05 Aug 2021, 11:22
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Question Stats:
52% (02:01) correct
47% (02:25) wrong based on 21 sessions
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If x > y, increasing the original price of an item by x% and then decreasing the new price by y% is equivalent to multiplying the original price by
A. \(\frac{1}{100(x-y)}\)
B. \(\frac{1}{100}(x-y-\frac{xy}{100})\)
C. \(\frac{x-y-xy}{100}\)
D. \(1+\frac{1}{100}(x-y+\frac{xy}{100})\)
E. \(1-\frac{x-y-xy}{100}\)
A. \(\frac{1}{100(x-y)}\)
B. \(\frac{1}{100}(x-y-\frac{xy}{100})\)
C. \(\frac{x-y-xy}{100}\)
D. \(1+\frac{1}{100}(x-y+\frac{xy}{100})\)
E. \(1-\frac{x-y-xy}{100}\)
If x > y, increasing the original price of an item by x% and then decr
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06 Aug 2021, 03:36
06 Aug 2021, 03:36
2
To make the calculations easy, take the numbers for \(x\) & \(y\)
Take the base value \(= 100\)
\(x = 30\)% and \(y = 20\)%
With a \(30\)% increase, the value will be \(130\), and when it is decreased by \(20\)%, it will be \(104\)
Hence overall \(4\)% increase.
Put the values of \(x\) & \(y\) in the options, only \(B\) will suffice and hence the answer.
B = \(\frac{1}{100}(x-y-\frac{xy}{100})\)
\((x-y-\frac{xy}{100}\)) = \(30 - 20 - \frac{30*20}{100}\) \(= 4\)
Answer B
Take the base value \(= 100\)
\(x = 30\)% and \(y = 20\)%
With a \(30\)% increase, the value will be \(130\), and when it is decreased by \(20\)%, it will be \(104\)
Hence overall \(4\)% increase.
Put the values of \(x\) & \(y\) in the options, only \(B\) will suffice and hence the answer.
B = \(\frac{1}{100}(x-y-\frac{xy}{100})\)
\((x-y-\frac{xy}{100}\)) = \(30 - 20 - \frac{30*20}{100}\) \(= 4\)
Answer B
Re: If x > y, increasing the original price of an item by x% and then decr
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06 Aug 2021, 09:26
06 Aug 2021, 09:26
Carcass wrote:
If x > y, increasing the original price of an item by x% and then decreasing the new price by y% is equivalent to multiplying the original price by
A. 1/100(x-y)
B. 1/100(x-y-xy/100)
C. x-y-xy/100
D. 1+1/100(x-y+xy/100)
A. 1/100(x-y)
B. 1/100(x-y-xy/100)
C. x-y-xy/100
D. 1+1/100(x-y+xy/100)
Hi. I am actually finding it hard to wrap my head around whether the given answers are indented properly.
Is the option A 1/((100)*(x-y)) or (x-y)/100
And for option B, (x-y-xy)/100 or x - y - (xy/100).
In this way, it feels quite confusing.
