GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
If the average (arithmetic mean) of u w x,y and z is 12.3, a
[#permalink]
22 May 2017, 01:08
22 May 2017, 01:08
1
Expert Reply
3
Bookmarks
00:00
Question Stats:
88% (01:15) correct
11% (01:13) wrong based on 72 sessions
Hide Show timer Statistics
If the average (arithmetic mean) of v, w, x, y and z is 12.3, and the average of v and w is 45.6, what is the average of x, y, and z?
Enter your value
Show: :: OA
-9.9
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: If the average (arithmetic mean) of u w x,y and z is 12.3, a
[#permalink]
22 May 2017, 15:19
22 May 2017, 15:19
2
Carcass wrote:
If the average (arithmetic mean) of v, w, x, y and z is 12.3, and the average of v and w is 45.6, what is the average of x, y, and z?
Enter your value
Show: :: OA
-9.9
The average (arithmetic mean) of v, w, x, y and z is 12.3
So, (v + w + x + y + z)/5 = 12.3
Multiply both sides by 5 to get: v + w + x + y + z = 61.5
The average of v and w is 45.6
So, (v + w)/2 = 45.6
Multiply both sides by 2 to get: v + w = 91.2
What is the average of x, y, and z?
We need the sum of x, y, and z
We have two equations:
v + w + x + y + z = 61.5
v + w = 91.2
Subtract the bottom equation FROM the top equation to get: x + y + z = -29.7
Divide both sides by 3 to get: (x + y + z) = (-29.7)/3 = -9.9
Answer:
Show: ::
-9.9
RELATED VIDEO
Re: If the average (arithmetic mean) of u w x,y and z is 12.3, a
[#permalink]
20 Feb 2023, 04:17
20 Feb 2023, 04:17
v+w+x+y+z=61.5
v+w=91.2
so,x+y+z=-29.7
so,average=-29.7/3=-9.9
v+w=91.2
so,x+y+z=-29.7
so,average=-29.7/3=-9.9
