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Retired Moderator
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Lines 3x + 4ky + 6 = 0, and kx -3y +9 = 0 intersect in the second quad
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09 Aug 2021, 06:32
09 Aug 2021, 06:32
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Question Stats:
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82% (02:54) wrong based on 17 sessions
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SUPER HARD
Lines \(3x + 4ky + 6 = 0\), and \(kx -3y +9 = 0\) intersect in the second quadrant
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Lines \(3x + 4ky + 6 = 0\), and \(kx -3y +9 = 0\) intersect in the second quadrant
Quantity A |
Quantity B |
Number of possible integral values of \(k\) |
4 |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Retired Moderator
Joined: 19 Nov 2020
Posts: 326
Given Kudos: 64
GRE 1: Q160 V152
Re: Lines 3x + 4ky + 6 = 0, and kx -3y +9 = 0 intersect in the second quad
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10 Aug 2021, 17:51
10 Aug 2021, 17:51
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two lines cross in the second quadrant, and they have different slopes (-/+ve), various intercepts (-6,9).
for x=0, equations become 4ky=-6 and 3y=9 and if y=-6, then k=1/4; for y=3, kx=0 or x=0 again.
for y=0, equations become 3x=-6 and kx=-9 resulting in -2k=-9, k=9/2
integral of k is along the line between two intercepts and possible cross points or 9/2-1/4= 17/4, which is greater than 4
Answer must be A
for x=0, equations become 4ky=-6 and 3y=9 and if y=-6, then k=1/4; for y=3, kx=0 or x=0 again.
for y=0, equations become 3x=-6 and kx=-9 resulting in -2k=-9, k=9/2
integral of k is along the line between two intercepts and possible cross points or 9/2-1/4= 17/4, which is greater than 4
Answer must be A
KarunMendiratta wrote:
SUPER HARD
Lines \(3x + 4ky + 6 = 0\), and \(kx -3y +9 = 0\) intersect in the second quadrant
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Lines \(3x + 4ky + 6 = 0\), and \(kx -3y +9 = 0\) intersect in the second quadrant
Quantity A |
Quantity B |
Number of possible integral values of \(k\) |
4 |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Re: Lines 3x + 4ky + 6 = 0, and kx -3y +9 = 0 intersect in the second quad
[#permalink]
12 Jan 2025, 09:21
12 Jan 2025, 09:21
Carcass pls explain
