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If the average (arithmetic mean) of 3, 6, 10, m and n is 9, then what
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09 Aug 2021, 15:28
09 Aug 2021, 15:28
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If the average (arithmetic mean) of 3, 6, 10, m and n is 9, then what is the average of m + 4 and n – 2 ?
(A) 9
(B) 13
(C) 14
(D) 18
(E) 26
(A) 9
(B) 13
(C) 14
(D) 18
(E) 26
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Re: If the average (arithmetic mean) of 3, 6, 10, m and n is 9, then what
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09 Aug 2021, 15:34
09 Aug 2021, 15:34
1
Carcass wrote:
If the average (arithmetic mean) of 3, 6, 10, m and n is 9, then what is the average of m + 4 and n – 2 ?
(A) 9
(B) 13
(C) 14
(D) 18
(E) 26
(A) 9
(B) 13
(C) 14
(D) 18
(E) 26
The average (arithmetic mean) of 3, 6, 10, m and n is 9
So, (3 + 6 + 10 + m + n)/5 = 9
Multiply both sides by 5 to get: 3 + 6 + 10 + m + n = 45
Simplify: 19 + m + n = 45
Subtract 19 from both sides to get: m + n = 26
What is the average of m + 4 and n – 2 ?
We get: average = [(m + 4) + (n - 2)]/2
Simplify: average = (m + n + 2)/2
Replace m + n to get: average = (26 + 2)/2
Simplify: average = (28)/2 = 14
Answer: C
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Re: If the average (arithmetic mean) of 3, 6, 10, m and n is 9, then what [#permalink]
09 Aug 2021, 15:34
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