\(x + y > y\)

Subtracting \(y\) from both sides;

\(x + y - y > y - y\)
\(x > 0\)

\(xy < x\)
Since, \(x\) is positive, we can divide both sides by \(x\);

\(\frac{xy}{x} < \frac{x}{x}\)
\(y < 1\)

Now, we have no idea how big \(x\) is, or how small \(y\) is from 1 i.e. is \(y\) 0.5 or -2

Therefore we do not have enough information to compare both the quantities.
Hence, option D

Through examples;

Let \(x = 2\) and \(y = 0 .5\)
\(x + y > y\)
\(2.5 > 0.5\)

\(xy < x\)
\(1 < 2\)

Here, Col. A > Col. B

Let \(x = 0.1\) and \(y = 0 .5\)
\(x + y > y\)
\(0.6 > 0.5\)

\(xy < x\)
\(0.05 < 0.1\)

Here, Col. A < Col. B