motion2020 wrote:
At the start of an experiment, a population consisted of x organisms. At the end of each month, after the start of the experiment, the population size increased by twice of its size at the beginning of that month. If the total population at the end of five months is greater than 1,000, what is the minimum possible value of x?
(A) 2
(B) 3
(C) 4
(D) 5
(E) 6
NOTE: Don't make the same mistake I made and ignore the words "
increased by" in the question.
So, each month, the population doesn't double; the population INCREASES by double the population from last month.
In other words, the population TRIPLES each month.
Let's start by using the
table method to list the population for each month.
# months elapsed | population0 | x
1 | (x)(3)
2 | (x)(3)(3)
3 | (x)(3)(3)(3)
4 | (x)(3)(3)(3)(3)
5 | (x)(3)(3)(3)(3)(3) = (3⁵)(x) = 243x
So 243x represents the population of organisms after 5 months.
We're told that which population is greater than 1,000.
So we can write: 243x > 1,000
Divide both sides of the inequality by 243 to get: x > 4.11
Since x must be an INTEGER, the minimum possible of x is 5
Answer: D