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GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 2508
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The table above shows daily energy usage for an office building and
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17 Aug 2021, 09:13
17 Aug 2021, 09:13
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Energy Usage Units - 11, 10, 8, 7
Number of Days of the respective unit- 4, 5, n, 3
The table above shows daily energy usage for an office building and the number of days that amount of energy was used. If the average (arithmetic mean) daily energy usage was greater than the median daily energy usage, what is the smallest possible value for n?
(A) 2
(B) 3
(C) 4
(D) 5
(E) 6
Number of Days of the respective unit- 4, 5, n, 3
The table above shows daily energy usage for an office building and the number of days that amount of energy was used. If the average (arithmetic mean) daily energy usage was greater than the median daily energy usage, what is the smallest possible value for n?
(A) 2
(B) 3
(C) 4
(D) 5
(E) 6
Re: The table above shows daily energy usage for an office building and
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20 Aug 2021, 15:27
20 Aug 2021, 15:27
1
Average= (7*3+8*n+10*5+11*4) / (3+n+5+4) = (115+8n)/(12+n). We need this value to be greater than the median.
Let's check the answer choice. As they are in sequential order, it's always good to start from answer choice (c).
When n = 4, the median = 10, average = 9.1875. Eliminate this. We need to decrease the value of the median so, we have to add more and more "8" in the series. So we will increase the value of n and check answer choices (d) and (e).
When n = 5, the median = 10, average = 9.11
When n = 6, the median = 9, average = 9.05 (This is the right answer choice)
Let's check the answer choice. As they are in sequential order, it's always good to start from answer choice (c).
When n = 4, the median = 10, average = 9.1875. Eliminate this. We need to decrease the value of the median so, we have to add more and more "8" in the series. So we will increase the value of n and check answer choices (d) and (e).
When n = 5, the median = 10, average = 9.11
When n = 6, the median = 9, average = 9.05 (This is the right answer choice)
Re: The table above shows daily energy usage for an office building and
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25 Aug 2021, 06:34
25 Aug 2021, 06:34
raf1061 wrote:
Average= (7*3+8*n+10*5+11*4) / (3+n+5+4) = (115+8n)/(12+n). We need this value to be greater than the median.
Let's check the answer choice. As they are in sequential order, it's always good to start from answer choice (c).
When n = 4, the median = 10, average = 9.1875. Eliminate this. We need to decrease the value of the median so, we have to add more and more "8" in the series. So we will increase the value of n and check answer choices (d) and (e).
When n = 5, the median = 10, average = 9.11
When n = 6, the median = 9, average = 9.05 (This is the right answer choice)
Let's check the answer choice. As they are in sequential order, it's always good to start from answer choice (c).
When n = 4, the median = 10, average = 9.1875. Eliminate this. We need to decrease the value of the median so, we have to add more and more "8" in the series. So we will increase the value of n and check answer choices (d) and (e).
When n = 5, the median = 10, average = 9.11
When n = 6, the median = 9, average = 9.05 (This is the right answer choice)
Could someone explain how you got the median values after substituting values for n
