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Re: A bag contains 10 bulbs and 5 torches, out of which 3 bulbs and [#permalink]
I used a shorter method and I am unsure if this works or not. KarunMendiratta and Carcass, please check:

# of working bulbs = 7
# of items to pick from = 15

CHOICE A = P( 2 not defective bulbs) = (7/15) * (6*14) = 1/5 = 20%
CHOICE B = 6/7

B>A
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Re: A bag contains 10 bulbs and 5 torches, out of which 3 bulbs and [#permalink]
Expert Reply
Not sure

QA tells us

The probability that both are bulbs or both are in working condition

Both are bulbs OR working conditions.

So you have to include

bulbs
defective bulbs
torches
defective torches
1 bulb and 1 defective torche
1 torche and 1 defective bulb
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Re: A bag contains 10 bulbs and 5 torches, out of which 3 bulbs and [#permalink]
GreNow wrote:
c

The probability of selecting 2 bulbs in a row is 2/3 * 9/14 = 3/7 added to the probability of selecting 2 items in working condition which happens to be the same 10/15 * 9/14 = 3/7 and together that's 6/7.


What's wrong with this solution?
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Re: A bag contains 10 bulbs and 5 torches, out of which 3 bulbs and [#permalink]
Defective bulbs = 3
Working bulbs = 7
Defective torches = 2
Working torches = 3

both working bulbs or Torches = 7/15x 6/14+ 3/15+2/14= 48/210= 24/105< 6/7. Ans:B
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Re: A bag contains 10 bulbs and 5 torches, out of which 3 bulbs and [#permalink]
GreNow wrote:
c

The probability of selecting 2 bulbs in a row is 2/3 * 9/14 = 3/7 added to the probability of selecting 2 items in working condition which happens to be the same 10/15 * 9/14 = 3/7 and together that's 6/7.


why is this incorrect?
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Re: A bag contains 10 bulbs and 5 torches, out of which 3 bulbs and [#permalink]
1
Expert Reply
----------Working------Defective-----Total
Bulb--------7---------------3-----------10
Torch-------3---------------2------------5
Total-------10--------------5-----------15

As you can see, there is an overlap between bulbs and working, which should be excluded.
Thus, P = P (both are bulbs) + P (both working) - P (both bulbs AND working).

1. P (both are bulbs):
10/15*9/14=3/7

2. P (both working):
10/15*9/14=3/7

3. P (both bulbs AND working):
7/15*6/14=1/5

P = 3/7+3/7-1/5=23/35 or 0.65

B is 0.85

B is the correct answer.

PS: great question but too tough for the GRE
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Re: A bag contains 10 bulbs and 5 torches, out of which 3 bulbs and [#permalink]
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