arjunbirNote: I refer the square root to sq.
Firstly, you can notice in the expression:
a= sq(8+sq63)
b= sq(8-sq63)
(a-b)^2 =
a^2-2ab+
b^2By replacing the expression, it gives:
[sq(8+sq63) - sq(8-sq63)]^2 =
8+sq63 - 2[sq(8+sq63)][sq(8-sq63)] +
8-sq63 =
16 -2
sq(8+sq63)sq(8-sq63)sq(AB)=
sqA*
sqB. .
So, going back to our formula, it gives us:
= 16 - 2 sq[(8+sq63)(8-sq63)]
Then, we use the identity a^2-b^2=(a-b)(a+b)
= 16 - 2 sq(64 - 63)
= 16 - 2 sq1 = 16-2 = 14