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GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 2506
Given Kudos: 1055
GPA: 3.39
Mr. and Mrs. Wiley have a child every J years. Their oldest child is
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24 Aug 2021, 05:21
24 Aug 2021, 05:21
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78% (01:20) correct
21% (01:09) wrong based on 14 sessions
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Mr. and Mrs. Wiley have a child every J years. Their oldest child is now T years old. If they have a child 2 years from now, how many children will they have in total?
(A) \(\frac{T+2}{J} + 1\)
(B) \(JT + 1\)
(C) \(\frac{J}{T} + \frac{1}{T}\)
(D) \(TJ - 1\)
(E) \(\frac{T+J}{J}\)
(A) \(\frac{T+2}{J} + 1\)
(B) \(JT + 1\)
(C) \(\frac{J}{T} + \frac{1}{T}\)
(D) \(TJ - 1\)
(E) \(\frac{T+J}{J}\)
Re: Mr. and Mrs. Wiley have a child every J years. Their oldest child is
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27 Aug 2021, 10:17
27 Aug 2021, 10:17
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1st child, 2nd child, 3rd child, ....... nth child (to be born after 2 yrs)
What is the difference between first and last terms (children)? (T + 2) yrs
What is the common difference (age difference between two consecutive kids)? J yrs
What is the number of terms (children)? (T + 2)/J + 1
(Number of terms of an AP is n = (Last term - First term)/Common Difference + 1. )
OR
Try with numbers:
They have a child every 3 years (J=3)
child 1 is 1 year old
ch 2 4y
ch 3 7y
ch 4 10y (oldest)
T=10
They have 4 children now
(10+2)/3 =(T+2)/J
After 2 years they will have (T+2)/J +1
What is the difference between first and last terms (children)? (T + 2) yrs
What is the common difference (age difference between two consecutive kids)? J yrs
What is the number of terms (children)? (T + 2)/J + 1
(Number of terms of an AP is n = (Last term - First term)/Common Difference + 1. )
OR
Try with numbers:
They have a child every 3 years (J=3)
child 1 is 1 year old
ch 2 4y
ch 3 7y
ch 4 10y (oldest)
T=10
They have 4 children now
(10+2)/3 =(T+2)/J
After 2 years they will have (T+2)/J +1
gmatclubot
Re: Mr. and Mrs. Wiley have a child every J years. Their oldest child is [#permalink]
27 Aug 2021, 10:17
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