Carcass
The highlighted part would be 1/2*1/2 = 1/4 and 1/4*3/4 = 3/16
The answer must be Col. B

Let us solve this question using Quadratic function (Parabola);
$f(p) = p(1-p)$
$f(p) = -p^2 + p$

In a Quadratic function with a < 0, the maximum value is y-coordinate of the vertex

x-coordinate of the vertex $= \frac{-b}{2a} = \frac{-1}{2(-1)} = \frac{1}{2}$
y-coordinate of the vertex $= -(\frac{1}{2})^2 + \frac{1}{2} = 1/4$

Col. A: $\frac{1}{4}$
Col. B: $\frac{1}{2}$

Hence, option B