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(x^2+1)(x+1)
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05 Jan 2020, 03:36
05 Jan 2020, 03:36
Expert Reply
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Question Stats:
77% (01:09) correct
22% (01:25) wrong based on 45 sessions
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\(x > 0\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Quantity A |
Quantity B |
\((x^2+1)\)\((x+1)\) |
\((x+1)^2(x-1)\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Re: (x^2+1)(x+1)
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05 Jan 2020, 03:45
05 Jan 2020, 03:45
2
Carcass wrote:
\(x > 0\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Quantity A |
Quantity B |
\((x^2+1)\)\((x+1)\) |
\((x+1)^2(x-1)\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
QTY A::
\((x^2+1)\)\((x+1)\)
QTY B::
\((x+1)^2(x-1)\) = \((x+1)(x+1)(x-1)\)
REMOVING x+1 from both quantities
QTY A : \((x^2+1)\)
QTY B : \((x+1)(x-1)\) = \((x^2-1) \)
Therefore QTY A > QTY B
(x^2+1)(x+1)
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27 Aug 2021, 01:24
27 Aug 2021, 01:24
But we can divide (x-1) both side,then
Qt. A = (x+1)(x+1)
Qt. B = (x+1)(x+1)
ans-C.
Qt. A = (x+1)(x+1)
Qt. B = (x+1)(x+1)
ans-C.
