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GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 2508
Given Kudos: 1053
GPA: 3.39
At the beginning of year 1, an investor puts [m]p[/m] dollars into an
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24 Aug 2021, 05:27
24 Aug 2021, 05:27
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Question Stats:
60% (02:25) correct
40% (02:41) wrong based on 15 sessions
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At the beginning of year 1, an investor puts \(p\) dollars into an investment whose value increases at a variable rate of \(x_n%\) per year, where \(n\) is an integer ranging from 1 to 3 indicating the year. If \(85 \lt x_n \lt 110\) for all \(n\) between 1 and 3, inclusive, then at the end of 3 years, the value of the investment must be between
A. $\(p\) and $\(2p\)
B. $\(2p\) and $\(5p\)
C. $\(5p\) and $\(10p\)
D. $\(10p\) and $\(25p\)
E. $\(25p\) and $\(75p\)
A. $\(p\) and $\(2p\)
B. $\(2p\) and $\(5p\)
C. $\(5p\) and $\(10p\)
D. $\(10p\) and $\(25p\)
E. $\(25p\) and $\(75p\)
Re: At the beginning of year 1, an investor puts [m]p[/m] dollars into an
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27 Aug 2021, 10:14
27 Aug 2021, 10:14
1
Expert Reply
The quick solution to this problem is to pick a convenient number in the allowed range of growth rates. If xnxn is always between 85 and 110, then the most convenient growth rate to pick is 100. An annual growth rate of 100% is exactly equivalent to doubling one's money. Doubling one's money three times is equivalent to multiplying one's investment by a factor of 8 (=23=23). The only range that includes $8p8p is the third range ($5p5p to $10p10p).
Computing the exact outer limits of the allowed range is much more cumbersome. We would have to cube 1.85 for the lower limit and 2.1 for the upper limit. The cube of 1.85 is 6.331625, and the cube of 2.1 is 9.261. These values fall between 5 and 10.
Answer: C.
Computing the exact outer limits of the allowed range is much more cumbersome. We would have to cube 1.85 for the lower limit and 2.1 for the upper limit. The cube of 1.85 is 6.331625, and the cube of 2.1 is 9.261. These values fall between 5 and 10.
Answer: C.
Re: At the beginning of year 1, an investor puts [m]p[/m] dollars into an
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25 Dec 2023, 19:01
25 Dec 2023, 19:01
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