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Remainder when 112th number in a sequence is divided by 3
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27 Aug 2021, 21:39
27 Aug 2021, 21:39
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Question Stats:
93% (00:36) correct
6% (03:47) wrong based on 16 sessions
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Given a sequence 3,6,9,...,999, what is the remainder when 112th number in the sequence is divided by 3?
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\(0\)
Re: Remainder when 112th number in a sequence is divided by 3
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28 Aug 2021, 07:39
28 Aug 2021, 07:39
1
The sequence: \(3, 6, 9, ... , 999\)
All the nos in the sequence are multipliers of \(3\), hence the remainder will be \(0\) for any term.
Answer 0
All the nos in the sequence are multipliers of \(3\), hence the remainder will be \(0\) for any term.
Answer 0
Re: Remainder when 112th number in a sequence is divided by 3
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29 Aug 2021, 18:10
29 Aug 2021, 18:10
As all the numbers in the sequence can be divided by 3 . The remainder will be 0 
