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At a school fundraiser, each member of the AV club sold 2/3 as many
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17 Aug 2021, 09:26
17 Aug 2021, 09:26
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43% (02:06) wrong based on 16 sessions
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At a school fundraiser, each member of the AV club sold \(\frac{2}{3}\) as many raffle tickets as each member of the chess club. If the AV has \(\frac{3}{5}\) as many members as the chess club, what fraction of all the tickets sold by the two clubs were sold by the AV club?
A) \(\frac{2}{7}\)
B) \(\frac{2}{5}\)
C) \(\frac{1}{2}\)
D) \(\frac{3}{5}\)
E) \(\frac{4}{7}\)
A) \(\frac{2}{7}\)
B) \(\frac{2}{5}\)
C) \(\frac{1}{2}\)
D) \(\frac{3}{5}\)
E) \(\frac{4}{7}\)
Re: At a school fundraiser, each member of the AV club sold 2/3 as many
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31 Aug 2021, 07:59
31 Aug 2021, 07:59
Does anyone has a solution to this problem?
At a school fundraiser, each member of the AV club sold 2/3 as many
[#permalink]
31 Aug 2021, 08:23
31 Aug 2021, 08:23
3
Let's take the no of members at chess club \(= 25\), so
the no of members at AV club \(= 15\)
Each member of the AV club sold \(\frac{2}{3}\) as many raffle tickets as each member of the chess club
let's say each member of the chess club sold \(3\) tickets, so each member of AV will sell \(2\) tickets.
No of tickets sold by AV \(= 2 * 15 = 30\) & by chess club \(= 3 * 25 = 75\)
Ratio = \(\frac{AV-club}{total} = \frac{30}{105}\) = \(\frac{2}{7}\)
Answer A
the no of members at AV club \(= 15\)
Each member of the AV club sold \(\frac{2}{3}\) as many raffle tickets as each member of the chess club
let's say each member of the chess club sold \(3\) tickets, so each member of AV will sell \(2\) tickets.
No of tickets sold by AV \(= 2 * 15 = 30\) & by chess club \(= 3 * 25 = 75\)
Ratio = \(\frac{AV-club}{total} = \frac{30}{105}\) = \(\frac{2}{7}\)
Answer A
Sirish123 wrote:
Does anyone has a solution to this problem?
